
What is "-1L" / "1L" in C? - Stack Overflow
The L specifies that the number is a long type, so -1L is a long set to negative one, and 1L is a long set to positive one. As for why ftell doesn't just return NULL, it's because NULL is used for …
What's the difference between `1L` and `1`? - Stack Overflow
Aug 10, 2011 · I often seen the symbol 1L (or 2L, 3L, etc) appear in R code. Whats the difference between 1L and 1? 1==1L evaluates to TRUE. Why is 1L used in R code?
c - What does 1L mean? - Stack Overflow
What does 1L mean? [duplicate] Asked 12 years, 11 months ago Modified 5 years, 3 months ago Viewed 40k times
java - Difference between 1L and (long) 1 - Stack Overflow
Dec 4, 2020 · 9 Explanation Performance-wise there is no difference. (long) 1 is a constant expression (because the 1 is directly known) and hence, by the rules of the Java Language …
java - What means 1L serialVersionUID? When could I use this …
What means 1L serialVersionUID? When could I use this default value 1L? Asked 11 years, 10 months ago Modified 3 years, 8 months ago Viewed 52k times
Error in loadNamespace(j <- i[[1L]], c(lib.loc, .libPaths ...
Dec 3, 2020 · Thanks for trying. Reinstalling did not work, unfortunately. Do you know if I need to do anything using Rtools once it is installed? Eg do I have to run it or import it separately into …
KERAS IN R: Error in Summary.factor (c (1L, 1L, 1L, 1L,1L, 1L, 1L, 1L ...
Jan 24, 2018 · This question shows research effort; it is useful and clear
C# short/long/int literal format? - Stack Overflow
Just to add that upper case and lower case of these literal suffixes are equivalent e.g. 1l and 1L both will be treated as long integer but certainly 1L is more readable than 1l.
Error in loadnamespace when knitting R_markdown to PDF
Nov 5, 2020 · Error in loadNamespace (j <- i [ [1L]], c (lib.loc, .libPaths ()), versionCheck = vI [ [j]]) : namespace 'xfun' 0.17 is already loaded, but >= 0.19 is required If you found an error as …
r - Error in na.fail.default: missing values in object - but no missing ...
library(nlme) corpart.lme.1=lme(tot_nochc~cor_partner+agecu+cor_partner *agecu, random = ~cor_partner+agecu+cor_partner *agecu |day, data=dt, na.action=na.exclude) We get …