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  1. How do you solve sqrt (6x-5)+10=3? - Socratic

    Mar 12, 2017 · √6x − 5+10 −10 = 3 −10 ⇒ √6x −5 = −7 square both sides (√6x − 5)2 = (− 7)2 ⇒ 6x − 5 = 49 add 5 to both sides. 6x−5 +5 = 49+ 5 ⇒ 6x = 54 divide both sides by 6 6x 6 = 54 6 ⇒ x = 9 As a …

  2. How do you use the quadratic formula to solve 6x ^ { 2} - 24x - 30= 0 ...

    Nov 19, 2016 · Explanation: After play with some of the pairs to combine #6, 24 and 30# #6x^2 - 24x - 30 = 0# can be factored to:

  3. Question #733f9 + Example - Socratic

    Let f (x)=6x^3-7x^2-9x-2 and substitute these values to x and you will find f (2)=0. This means that x=2 is one of the roots and thus f (x) is divisivle by (x-2).

  4. What are the real zeros of this function #f (x)=3x^3+6x^2 ... - Socratic

    f (x) has zeros +-sqrt (5) and -2 Given: f (x) = 3x^3+6x^2-15x-30 Note that all of the terms are divisible by 3. In addition, the ratio of the first and second terms is the same as that of the third and fourth terms.

  5. Question #9d6c7 - Socratic

    Let "mass of X" = x and "mass of O" = y. y/ (x + y) = 0.6 y = 0.6x + 0.6y 0.4y = 0.6x y = (0.6x)/0.4 = 1.5x Let "mass of x = 32 u". Then "mass of O = 1.5 × 32 u = 48 u". ulbb ("Element"color (white) …

  6. How do you factor #6x^2+x-1# - Socratic

    Jan 29, 2017 · 6x^2+x-1 = (2x+1) (3x-1) Here are a couple of methods (in no particular order): Method 1 Note that: (ax+1) (bx-1) = abx^2+ (b-a)x-1 Comparing with: 6x^2+x-1 we want to find a, b such that …

  7. Question #80b00 - Socratic

    Measure of angle LhatOM = 48^0 7x-92+6x+12=180 1) Combine like terms 7x - 92 + 6x + 12 =180 13x - 80= 180 2) Add color (blue) (80) to both sides (13x) - cancel80 color (blue) (+ cancel80) = 180 color …

  8. How do you solve this system of equations: 3y + 6x = - 24 ... - Socratic

    Using [1] 3y+6x=-24 3y=-24-6x color (blue) (y=-8-2xcolor (white) (888) [3] Substituting [3] in [2] z=-2 (-8-2x)-16 z=16+4x-16 z=4x Now find y in terms of x. This is equation [3] we found earlier.

  9. Find all real zeros of the polynomial function. f (x) = 6x^3 ... - Socratic

    0, 1, 3 To solve this, we set the equation equal to 0 and factor it. First, we can factor out 6x to get 6x(x^2-4x+3)=0. Next we can factor out the area in parentheses. To do this, we need to find two …

  10. How do you use the important points to sketch the graph of y = x^2 − …

    How do you use the important points to sketch the graph of y = x2 − 6x + 1? Algebra Quadratic Equations and Functions Quadratic Functions and Their Graphs